vue.js实现只弹一次弹框

核心代码是 getCookie()部分,控制弹框的显示隐藏则在 created()中。

<template>
 <div v-if="isShow"> <!--最外层背景-->
 <div class="popup_container"> <!--居中的容器-->
 <img @click="noPopup" src="delete.png" alt=""> <!--关闭弹框-->
 <div class="popup_text"> <!--内容部分-->
 Lorem ipsum dolor sit amet, consectetur adipisicing elit. At, atque ea eveniet laudantium magni, maiores nam nihil non numquam odio pariatur perferendis placeat quas quasi sit soluta, sunt ullam voluptatibus. 
 </div>
 </div>
 </div>
</template>
<script>
 export default {
 data(){
 return{
 isShow: true,
 }
 },
 created(){
 if (this.getCookie('popped') == ''){ //cookie 中没有 popped 则赋给他一个值（此时弹框显示）
 document.cookie = "popped = yes";
 }else{
 this.isShow = false; //若cookie 中已经有 popped 值，则弹框再不会显示
 }
 },
 methods: {
 noPopup(){
 this.isShow = false;
 },
 getCookie(Name) { //cookie
 var search = Name + "=";
 var returnValue = "";
 if (document.cookie.length > 0) {
 var offset = document.cookie.indexOf(search);
 if (offset !== -1) {
 offset += search.length;
 var end = document.cookie.indexOf(";", offset);
 if (end == -1){
 end = document.cookie.length;
 }
 returnValue = decodeURIComponent(document.cookie.substring(offset, end));
 }
 }
 return returnValue;
 },
 },
 }
</script>
<style scoped>
 /*样式部分*/
</style>